WAEC GCE Chemistry Essay Answers Live
Chemistry Essay Answers
(1a)
(i)
Mass concentration of
B=3.95/750*1000
=5.2g/dm
VA=22.70cm^3 VB=25.0cm^3
(ii)
Concentration of B in mol/dm^3
=Concentration in g/dm^3/Molar mass
in g/mol
Molar mass of Na2CO3
=(23*2)+(12)+(16*3) =46+12+48
=106g/mol
Concentration in mol/dm^3=5.27/106
=0.0497mol/dm^3
(iii)
CAVA/CBVB=nA/nB
(CA*22.70)/(0.0497*25)=1/1
CA=(0.0497*25*1)/22.70*1)
CA=0.0548mol/dm^3
(iv)
CA=concentration in g/dm/molar mass
Molar mass of A=H2SO4
=(1*2)+32+(16*4)
=2+32+64
=98g/mol 0.0548=concentration in g/dm^3/98
Concentration of A in g/
dm^3=0.0548*98
=5.37g/dm^3
Thanks.
But what about the remaining question.
I will be greatfull if I can get d remaining questions.